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If ABC is an obtuse angled triangle, obtuse angled at B and if AD⊥CB Prove that AC2 =AB2 + BC2+2BCxBD
Ans: AC2 = AD2 + CD2
= AD2 + (BC + BD)2
= AD2 + BC2 + 2BC.BD+BD2
= AB2 + BC2 + 2BC.BD
if Sn =3n²+n, find the A.P.
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3x^2+19x-14=0
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