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Now let's move into the next technique for solving systems of equations. As we illustrated in the example the method of substitution will frequently force us to deal with fractions, which adds to the probability of mistakes. This second method will not have this difficulty. Well, that's not totally true. If fractions are going illustrated they will only illustrates in the final step and they will only show up if the solution contains fractions.
This second technique is called the method of elimination. In this technique we multiply one or both of the equations by appropriate numbers (i.e. multiply every term in the equation by the number) so that one of the variables will have the similar coefficient along with opposite signs. Then next step is to summing up the two equations together. Because one of the variables had the same coefficient with opposite signs it will be eliminated when we add the two equations. The result will be single equation which we can solve for one of the variables. Once this is done substitute this answer back into one of the original equations.
If P (x) is a polynomial of degree n then P (x) will have accurately n zeroes, some of which might repeat. This fact says that if you list out all the zeroes & listing each one
6u+5>2
hello! at my school we are learning how to solve two-step equations but i am having a little trouble. can you please help me?
y=x^2+2x-15
if a-b equals 73 what is a
how many does a rhombus have
To find the calorie density (D) in calories per ounce of food that contains c carories and weight w ounces is given by D=C/w
i want the limits of this equation
2.3*10^3,3.7*10^2,6.5*10^3
An artifact was found and tested for its carbon-14 content. If 86% of the original carbon-14 was still present, what is its probable age (to the nearest 100 years)? (Carbon-14 has
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