Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
(a) Draw neatly and accurately the Merchant force circle diagram. Mention clearly the forces involved, the constructional steps and the assumptions made [do not derive the forces]
(b) For an orthogonal process on a mild steel, using the following data :
Depth of cut = 0.3 mm
Chip thickness = 0.85 mm
Angle = 10o
Horizontal component of cutting force = 900 N
Vertical component of cutting force = 450 N
Determine :
(i) The coefficient of function b/w the tool & the Chip.
(ii) Shear plane angle.
(iii) Friction angle
(iv) Compressive force on sheer plane.
(v) Shear force on the shear plane.
(vi) Resultant cutting force.
Explain clearly the formulas for all of the above & then solve.
In conveyor belts calculations, if it is required of me to calculate "The Power transmitted by the drive,at the specific efficiency" Which power are they reffering to?
Question: A 4- pole DC motor is operated as a separately excited motor. When the motor is externally driven at 1800 rpm with rated field current and zero armature current,
A cantilever beam of 4 metre length is loaded with uniformly distributed load of 20 KN/m throughout the whole beam. It is also loaded with 30 KN operating at 3m from the fixed end
State and prove parallelogram law forces
The square cross sections A and B are shown in Fig Q1, the dimensions b = 80 mm, thickness t = 10 mm. A shear force V is applied at the cross section, calculate the maximum she
how to produce a design that meets the specification given: Beam Dimensions W, H and T, where H=2W and T=W/20 • Bolt Size D1 • Side Plate thickness T2 and width W2 • Cradle Plat
Pressure - Thermodynamics: While working in the system, thermodynamic medium exerts a force on boundaries of vessel in which it is kept. The vessel may be a container, or an e
Angle of twist is zero on the shaft: A shaft 10 m long and 100 mm diameter during its length is fixed at the ends and is subjected to two opposite torques of 8 kN-m and 10 kN-
Backup Purge Backup purge gas can also be used to protect the under side of the weld and its adjacent base metal surfaces from oxidation on the time of welding . Uniformity
Air at 1 atm, 300K, and Re = 50,000: a. Flow across the cylinder with a diameter of 10 cm. b. Flow inside a tube with a diameter of 10 cm. c. flow along the flat plate of
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd