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#question ..
Sketch the graph through the process of finding the zeroes Example Sketch the graph of P ( x ) = x 4 - x 3 - 6x 2 . Solution
f(x)=5x-3 g(x)=-2x^2-3 find f(-3 )and g(5)
Properties of f( x ) = b x 1. The graph of f( x ) will always have the point (0,1). Or put another way, f(0) = 1 in spite of of the value of b. 2. For every possible b b x
123/4=
what is the range of f(x)=2x+2
if I have the equation 3(x+4y)+5(2x-y)an then I change it into (3x+12y)+(10x-5y) what property is it
the problem is 6x+3y=-24. is tells me to graph using y=mx+b format but i don''t know how to get to that point.
Let's begin with x 2 + bx and notice that the x 2 hold a coefficient of one. That is needed in order to do this. Now,
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