Example of function evaluations, Algebra

Assignment Help:

Given  f ( x ) = x2 - 2 x + 8 and  g( x ) = √(x+ 6) evaluate f (3) and g(3)

Solution

Okay we've two function evaluations to do here and we've also obtained two functions so we're going to decide which function to employ for the evaluations. Here the key is to notice the letter that is in front of the parenthesis.  For f(3) we will use the function f( x ) and for

g (3) .we will employ g ( x ) .  In other terms, we just have to make sure that the variables match up.

Following are the evaluations for this part.

f(3) = (3)2  - 2 (3) +8 = 9 - 6 + 8 = 11

g(3) =√(3+6) =√9=3


Related Discussions:- Example of function evaluations

Graphing, the problem is 6x+3y=-24. is tells me to graph using y=mx+b forma...

the problem is 6x+3y=-24. is tells me to graph using y=mx+b format but i don''t know how to get to that point.

LCD, I dont understand why the least common denominator to the problem (3/2...

I dont understand why the least common denominator to the problem (3/2x) minus (1/2(x+10)) equals 1 is 2x(x+10)

Eoc review, three consecutive odd integers such that the s f the first and ...

three consecutive odd integers such that the s f the first and second is 31 less than 3 times the third. find the inters.

Logaritmos, si el log de 28 en base 14 es a cuanto es el log de 16 en base ...

si el log de 28 en base 14 es a cuanto es el log de 16 en base 49

Help me solve please, Given a = 2^4 * 3^3 * 7 * 13 and b = 2^3 * 3^2 * ...

Given a = 2^4 * 3^3 * 7 * 13 and b = 2^3 * 3^2 * 5^2 * 11 * 17 (Note ^ is my symbol for exponent) find the greatest common denominator of a and b. Find the least common mult

DEMAND AND SUPPLY, Qs1=-7+P1 (2) Qd1=15-P1+2P2+P3 (3) Qs1=Qd1

Qs1=-7+P1 (2) Qd1=15-P1+2P2+P3 (3) Qs1=Qd1

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd