Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Given f ( x ) = x2 - 2 x + 8 and g( x ) = √(x+ 6) evaluate f (3) and g(3)
Solution
Okay we've two function evaluations to do here and we've also obtained two functions so we're going to decide which function to employ for the evaluations. Here the key is to notice the letter that is in front of the parenthesis. For f(3) we will use the function f( x ) and for
g (3) .we will employ g ( x ) . In other terms, we just have to make sure that the variables match up.
Following are the evaluations for this part.
f(3) = (3)2 - 2 (3) +8 = 9 - 6 + 8 = 11
g(3) =√(3+6) =√9=3
Kevin randomly selected 1 card from a Standard deck of 52 cards. what is the probabilty that he will get the king of hearts?? Multiple choice .... 4/13.... 17/52...... 13/4..... 5
Taylor is 7 years younger than Lisa Lila is 3 x Lisa''s age if Lisa''s age is represented by x create an expression that represents the total age of all three girls
what is the range of f(x)=2x+2
omar loves bags of potato chips and ice cream bars, and they have fat and calories as follows: bags of potato chips contain 12 grams of fat and 325 calories; ice cream bars contain
There are several quantities out there within the world which are governed (at least for a short time period) by the equation,
Z=4X1+10X2
Question 1 [7 marks] The reduced row echelon form of ? ? ? ? ? ? ? ? ? ? ? ? 3 4 17 22 1 2 5 row a b A is equal to ? ? ? ? ? ? ? ? ? ? ? ? 0 0 0 0 0 0 1 2 1 2 0 3 R . (a) What can
(-3) EVALUATE X3 -2X2 + 6X -64
how to use the factor theorem
1/1+x+1/y+1/1+z+1/x+1/1+y+1/z=1
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: info@expertsmind.com
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd