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By Using the discriminant find out which solution set we obatin for each of the following quadratic equations.
13x2 +1= 5x
Solution
Firstly get the equation in standard form.
13x2 - 5x + 1 = 0
Then we have,
a = 13 b = -5 c=1
Plugging in the discriminant gives,
b2 - 4ac = ( -5)2 - 4 (13) (1) =-27
The discriminant is negative & thus we will have two complex solutions. For reference reason the actual solutions are,
find c when t=7
Sketch the graph of function. f ( x ) =3x + 6 /x -1 Solution Thus, we'll start off with the intercepts. The y-intercept is, f (0) =6/-1=-6⇒ (0, -6)
9x^4-x^2=0 step by step
5(-4x+70+5
280/388
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how to find the zero of an equation
2x^4-11x^3+19x^2-13x+3
A v\certain mountain had an elevation of 19,063 ft. In 1911 the glacier on this peek covered 8 acres. by 2000 this glacier had melted to only 1 acre. what is the yearly rate of ch
if the roots of a quadratic equation are (-2+sqrt 6) and (-2-sqrt 6), what is the equation in ax^2+bx+c=0 form?
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