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To delete an element in the list at the end, we can delete it without any difficult. But, assume if we desire to delete the element at the straining or middle of the list, then, we ought to rewrite all the elements after the position where the element that ought to be deleted exists. We ought to shift (r+1)th element to rthposition , where 'r' refer for position of deleted element in the list, the (r + 2)th element to (r + 1)th position, and it will continue till the (n)th element to ( n-1 )th position, where n refer to the number of elements in the list, and after that the count is decremented.
From the above instance, if we desire to delete an element '44' from the list. We ought to shift 55 to the 4th position, 66 to the 5th position, and 77 to the 6th position.
Before deletion
Count 1 2 3 4 5 6 7
11
22
33
44
55
66
77
Step 1
Step 2
Step 3
Count 1 2 3 4 5 6
Inorder traversal: The left sub tree is visited, then the node and then right sub-tree. Algorithm for inorder traversal is following: traverse left sub-tree visit node
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Run time complexity of an algorithm is depend on
draw a flowchart which prints all the even numbers between 1-50
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