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Q. Calculate that how many key comparisons and assignments an insertion sort makes in its worst case?
Ans:
The worst case performance occurs in insertion sort occurs when the elements of the input array are in descending order. In that case, the first pass requires one comparison, the second pass requires two comparisons, third pass three comparisons till the kth pass requires (k-1), and in the end the last pass requires (n-1) comparisons. Therefore, we obtain the total numbers of comparisons as follows : f(n) = 1+2+3+.........+(n-k)+.....+(n-2)+(n-1) = n(n-1)/2 = O(n2)
The worst case performance occurs in insertion sort occurs when the elements of the input array are in descending order. In that case, the first pass requires one comparison, the second pass requires two comparisons, third pass three comparisons till the kth pass requires (k-1), and in the end the last pass requires (n-1) comparisons. Therefore, we obtain the total numbers of comparisons as follows :
f(n) = 1+2+3+.........+(n-k)+.....+(n-2)+(n-1)
= n(n-1)/2
= O(n2)
Using the cohen sutherland. Algorithm. Find the visible portion of the line P(40,80) Q(120,30) inside the window is defined as ABCD A(20,20),B(60,20),C(60,40)and D(20,40)
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We have discussed already about three tree traversal methods in the earlier section on general tree. The similar three different ways to do the traversal -inorder , preorder, and p
Q. Explain the technique to calculate the address of an element in an array. A 25 × 4 matrix array DATA is stored in memory in 'row-major order'. If base address is 200 and
Let us assume a file of 5 records that means n = 5 And k is a sorted array of keys of those 5 records. Let key = 55, low = 0, high = 4 Iteration 1: mid = (0+4)/2 = 2
I =PR/12 Numbers of years .Interest rate up to 1yrs . 5.50 up to 5yrs . 6.50 More than 5 yrs . 6.75 design an algorithm based on the above information
I want to study example
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