Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Q. The reason bubble sort algorithm is inefficient is that it continues execution even after an array is sorted by performing unnecessary comparisons. Therefore, the number of comparisons in the best and worst cases both are same. Modify the algorithm such that it will not make the next pass when the array is already sorted.
Ans:
The bubble sort continues the execution even after an array is sorted. To avoid unnecessary comparisons we add a Boolean variable say switched and initialize it by True in the starting. Along with the "for" loop, we hear add the condition (switched=true) and make it false inside the outer for loop. If a swapping is done then the value of switched is made true. Thus if no swapping has been done in the first pass, then no more comparisons will be done further and the program shall exit. The algorithm after modifying it in the above stated manner will be as follows:- void bubble(int x[],int n) { int j,pass,hold; bool switched=true; for(pass=0;pass { switched=false; for(j=0;j { switched=true; hold=x[j]; x[j]=x[j+1]; x[j+1]=hold; } } }
The bubble sort continues the execution even after an array is sorted. To avoid unnecessary comparisons we add a Boolean variable say switched and initialize it by True in the starting. Along with the "for" loop, we hear add the condition (switched=true) and make it false inside the outer for loop. If a swapping is done then the value of switched is made true. Thus if no swapping has been done in the first pass, then no more comparisons will be done further and the program shall exit.
The algorithm after modifying it in the above stated manner will be as follows:-
void bubble(int x[],int n)
{
int j,pass,hold;
bool switched=true;
for(pass=0;pass { switched=false; for(j=0;j { switched=true; hold=x[j]; x[j]=x[j+1]; x[j+1]=hold; } } }
switched=false;
for(j=0;j { switched=true; hold=x[j]; x[j]=x[j+1]; x[j+1]=hold; } } }
switched=true; hold=x[j]; x[j]=x[j+1];
x[j+1]=hold;
}
Question 1 Describe the following- Well known Sorting Algorithms Divide and Conquer Techniques Question 2 Describe in your own words the different asymptotic func
State the Introduction to pseudocode No specific programming language is referred to; development of algorithms by using pseudocode uses generic descriptions of branching, loop
Byteland county is very famous for luminous jewels. Luminous jewels are used in making beautiful necklaces. A necklace consists of various luminous jewels of particular colour. Nec
Krushkal's algorithm uses the concept of forest of trees. At first the forest contains n single node trees (and no edges). At each of the step, we add on one (the cheapest one) edg
Suppose that there is a Beta(2,2) prior distribution on the probability theta that a coin will yield a "head" when spun in a specified manner. The coin is independently spun 10 tim
One can change a binary tree into its mirror image by traversing it in Postorder is the only proecess whcih can convert binary tree into its mirror image.
Define Dynamic Programming Dynamic programming is a method for solving problems with overlapping problems. Typically, these sub problems arise from a recurrence rel
What is the difference between a grounded header link list and a circular header link list? A header linked list is a linked list which always having a special node, known as t
The best average behaviour is shown by Quick Sort
HSV Colour Model Instead of a set of colour primaries, the HSV model uses colour descriptions that have a more intuitive appeal to a user. To give a colour specification, a use
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd