Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Q. The reason bubble sort algorithm is inefficient is that it continues execution even after an array is sorted by performing unnecessary comparisons. Therefore, the number of comparisons in the best and worst cases both are same. Modify the algorithm such that it will not make the next pass when the array is already sorted.
Ans:
The bubble sort continues the execution even after an array is sorted. To avoid unnecessary comparisons we add a Boolean variable say switched and initialize it by True in the starting. Along with the "for" loop, we hear add the condition (switched=true) and make it false inside the outer for loop. If a swapping is done then the value of switched is made true. Thus if no swapping has been done in the first pass, then no more comparisons will be done further and the program shall exit. The algorithm after modifying it in the above stated manner will be as follows:- void bubble(int x[],int n) { int j,pass,hold; bool switched=true; for(pass=0;pass { switched=false; for(j=0;j { switched=true; hold=x[j]; x[j]=x[j+1]; x[j+1]=hold; } } }
The bubble sort continues the execution even after an array is sorted. To avoid unnecessary comparisons we add a Boolean variable say switched and initialize it by True in the starting. Along with the "for" loop, we hear add the condition (switched=true) and make it false inside the outer for loop. If a swapping is done then the value of switched is made true. Thus if no swapping has been done in the first pass, then no more comparisons will be done further and the program shall exit.
The algorithm after modifying it in the above stated manner will be as follows:-
void bubble(int x[],int n)
{
int j,pass,hold;
bool switched=true;
for(pass=0;pass { switched=false; for(j=0;j { switched=true; hold=x[j]; x[j]=x[j+1]; x[j+1]=hold; } } }
switched=false;
for(j=0;j { switched=true; hold=x[j]; x[j]=x[j+1]; x[j+1]=hold; } } }
switched=true; hold=x[j]; x[j]=x[j+1];
x[j+1]=hold;
}
This unit discussed about data structure called Arrays. The easiest form of array is a one-dimensional array which may be described as a finite ordered set of homogeneous elements
Q. Describe what do you understand by the term array? How does an array vary from an ordinary variable? How are the arrays represented in the specific memory?
Define Complete Binary Tree Complete Binary Tree:- A whole binary tree of depth d is that strictly binary tree all of whose leaves are at level D.
compare and contrast the bubble sort,quick sort,merge sort and radix sort
Consider the digraph G with three vertices P1,P2 and P3 and four directed edges, one each from P1 to P2, P1 to P3, P2 to P3 and P3 to P1. a. Sketch the digraph. b. Find the a
Phong Shading Phong shading too is based on interpolation, but instead of interpolating the colour value, it is the normal vector, which is interpolated for each point and a co
Write a program to simulate searching over a hashed file, with different assumptions for the sizeof file pages.Write a program to perform equality search operations on the hashed f
N = number of rows of the graph D[i[j] = C[i][j] For k from 1 to n Do for i = 1 to n Do for j = 1 to n D[i[j]= minimum( d ij (k-1) ,d ik (k-1) +d kj (k-1)
Explain the Memory Function method The Memory Function method seeks to combine strengths of the top down and bottom-up approaches to solving problems with overlapping su
It is a naturally occurring sorting method exemplified through a card player arranging the cards dealt to him. He picks up the cards like they are dealt & added them into the neede
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd