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How to Solving One-Step Equations?
Equations, where one math operation is acting on the variable, can be solved in one step. The trick is to get the variable x by itself - isolate the variable.The following 4 equations involve one math operation.x+ 2 = 6x-2 = 62x = 6x/2 = 6(2x means 2 multiplied times x)In the above examples, x is the variable. The math operations are: 1.) add, 2.) subtract, 3.) multiply, and 4.) divide. Addition Equations : To solve for addition equations, subtract the number being added to x on both sides of the equation.Example: Solve for x in the equation x + 5 = 13.x + 5 = 13 x + 5 - 5 = 13 - 5 Subtract five from both sides.x = 8 Simplify.8 + 5 = 13 Check the answer.
Subtraction Equations : To solve for subtraction equations, add the number being subtracted from x on both sides of the equation.Example: Solve for x in the equation x - 3 = 19.x - 3 = 19 x - 3 + 3 = 19 + 3 Add 3 to both sides.x = 22 Simplify.22 - 3 = 19 Check the answer.
how to answer this: 3x2-18x-60
Describe the Basic Concepts and Terminology? Somebody tells you that x = 5 and y = 3. "What does it all mean?!" you shout. Well here's a picture: This picture is what's
If the squared difference of the zeros of the quadratic polynomial x 2 + p x + 45 is equal to 144 , find the value of p.
What is the ratio of the areas of sectors I and II ? (Ans:4:5) Ans: Ratio will be 120/360 Π r 2 : 150/360 Π r 2 4/12 : 5/12 =
Convert each of the following points into the specified coordinate system. (a) (-4, 2 Π /3) into Cartesian coordinates. (b) (-1,-1) into polar coordinates. Solution
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The ratio of the sum of first n terms of two AP's is 7n+1:4n+27. Find the ratio of their 11th terms . Ans: Let a 1 , a 2 ... and d 1 , d 2 be the I terms are Cd's of t
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Express the GCD of 48 and 18 as a linear combination. (Ans: Not unique) A=bq+r, where o ≤ r 48=18x2+12 18=12x1+6 12=6x2+0 ∴ HCF (18,48) = 6 now 6
If two vertices of an equilateral triangle are (0, 0) and (3, 0), find the third vertex. [Ans: 3/2 , 3/√ 3/2 or 3/2, -3√ 3/2] Ans: OA = OB = AB OA 2 = OB 2 = AB 2
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