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How to Solving One-Step Equations?
Equations, where one math operation is acting on the variable, can be solved in one step. The trick is to get the variable x by itself - isolate the variable.The following 4 equations involve one math operation.x+ 2 = 6x-2 = 62x = 6x/2 = 6(2x means 2 multiplied times x)In the above examples, x is the variable. The math operations are: 1.) add, 2.) subtract, 3.) multiply, and 4.) divide. Addition Equations : To solve for addition equations, subtract the number being added to x on both sides of the equation.Example: Solve for x in the equation x + 5 = 13.x + 5 = 13 x + 5 - 5 = 13 - 5 Subtract five from both sides.x = 8 Simplify.8 + 5 = 13 Check the answer.
Subtraction Equations : To solve for subtraction equations, add the number being subtracted from x on both sides of the equation.Example: Solve for x in the equation x - 3 = 19.x - 3 = 19 x - 3 + 3 = 19 + 3 Add 3 to both sides.x = 22 Simplify.22 - 3 = 19 Check the answer.
the sides of a right angle triangle are a,a+d,a+2d with a and d both positive.the ratio of a to d a)1:2 b)1:3 c)3:1 d)5:2 answer is (c) i.e. 3:1 Solution: Applying
find the ratio of each of the following in simplest form 1] 9 months to 7 by 4
You have just renegotiated the interest rate of your home mortgage loan. (This is called rate modification.) The original loan of $400,000 carries an interest rate is 6% has an or
What percent of the figure below is shaded? Break the rectangle into eighths as shown below. The shaded part is 6/8 or 3/4 ; 3/4 is 75%.
Calculate the Probability A bag contains 80 balls of such 20 are red, 25 are blue and 35 are white. A ball is picked at random what is the probability that the ball picked is
Solve 4 sin 2 ( t ) - 3 sin ( t /3)= 1 . Solution Before solving this equation let's solve clearly unrelated equation. 4x 2 - 3x = 1 ⇒ 4x 2 - 3x -1 = ( 4x + 1) ( x
Proof of the Derivative of a Constant : d(c)/dx = 0 It is very easy to prove by using the definition of the derivative therefore define, f(x) = c and the utilize the definiti
how to get harmonic problems with answer
It is totally possible that a or b could be zero and thus in 16 i the real part is zero. While the real part is zero we frequently will call the complex numbers a purely imaginar
Let's start things by searching for a mixing problem. Previously we saw these were back in the first order section. In those problems we had a tank of liquid with several kinds of
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