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How to Solving One-Step Equations?
Equations, where one math operation is acting on the variable, can be solved in one step. The trick is to get the variable x by itself - isolate the variable.The following 4 equations involve one math operation.x+ 2 = 6x-2 = 62x = 6x/2 = 6(2x means 2 multiplied times x)In the above examples, x is the variable. The math operations are: 1.) add, 2.) subtract, 3.) multiply, and 4.) divide. Addition Equations : To solve for addition equations, subtract the number being added to x on both sides of the equation.Example: Solve for x in the equation x + 5 = 13.x + 5 = 13 x + 5 - 5 = 13 - 5 Subtract five from both sides.x = 8 Simplify.8 + 5 = 13 Check the answer.
Subtraction Equations : To solve for subtraction equations, add the number being subtracted from x on both sides of the equation.Example: Solve for x in the equation x - 3 = 19.x - 3 = 19 x - 3 + 3 = 19 + 3 Add 3 to both sides.x = 22 Simplify.22 - 3 = 19 Check the answer.
Rules of Integration 1. If 'k' is a constant then ∫Kdx = kx + c 2. In
Average cost function : Now let's turn our attention to the average cost function. If C ( x ) is the cost function for some of the item then the average cost function is,
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Evaluate following limits. Solution: Let's begin this one off in the similar manner as the first part. Let's take the limit of each piece. This time note that since our l
Now we have to look at rational expressions. A rational expression is a fraction wherein the numerator and/or the denominator are polynomials. Here are some examples of rational e
A long distance calls costs x cents for the first minute and y cents for every additional minute. How much would a 5-minute call cost? The cost of the call is x cents plus y ti
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class 10 Q.trigonometric formula of 1 term
Differentials : In this section we will introduce a notation. We will also look at an application of this new notation. Given a function y = f ( x ) we call dy & dx differen
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