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In a right triangle ABC, right angled at C, P and Q are points of the sides CA and CB respectively, which divide these sides in the ratio 2: 1. Prove that 9AQ 2 = 9AC 2 +4BC 2
Homework help???
((1/x^1/2-(x-1)^1/2)+(1/(5-3(x-1)^2)^1/2)
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