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A jar contains 54 marbles each of which is blue , green or white. The probability of selecting a blue marble at random from the jar is 1/3 and the probability of selecting a green marble at random is 4/9 . How many white marbles does the jar contain? (Ans:12)
Ans: Let there be b blue, g green and w white marbles in the marbles in the jar. Then, b + g + w = 54
∴ P (Selecting a blue marble) = b/54
It is given that the probability of selecting a blue marble is 1/3 .
∴ 1/3 = b/54 => b = 18
We have,
P(Selecting a green marble) = 4/9
=> g/54 = 4/9
[Q P (Selecting a green marble) = 4/9 (Given)]
=> g = 24
Substituting the values of b and g in (i), we get
18 + 24 + w = 54 => w = 12
Example of Integration by Parts - Integration techniques Some problems could need us to do integration by parts many times and there is a short hand technique that will permit
g/6-2+(9/9)
where will we use least cost method
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compare: 643,251: 633,512: 633,893. The answer is 633,512.
how will you explain the listing method?
We know that a factor is a quantity which divides the given quantity without leaving any remainder. Similar to LCM above we can find a highest common factor (HCF)
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