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Now, we've got some terminology to get out of the way. Multiplicity k If r is a zero of a polynomial and the exponent on the term that produced the root is k then we say t
y=4x-5 y=2x+1
Sketch the graph of P ( x ) = 5x 5 - 20x 4 + 5x 3 + 50x2 - 20x - 40 . Solution We set up the zeroes & multiplicities of this polynomial in the previous section hence
how do you solve function of x ?
how do I solve the equation 0.6(x+60)+0.2x=52
4x+2y=10
How would I solve the reflection of y= (-x)^2
2x-3x=16 what do i do?.
use substitution method to solve this equation x+y=20 y= -5x
Whereas we are on the subject of function evaluation we have to now talk about piecewise functions. Actually we've already seen an instance of a piecewise function even if we didn'
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