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Translate into an equation: A number increased by 19 equals 77 (let the number be represented by k)
y-5=2x
y+7 3y-2 --- = 1 + ---- 3 5
how do you solve y+2=5x-4
Kelly has 24 and quarters worth $3.60. How many quarters does she have?
3x/4 = 2
si el log de 28 en base 14 es a cuanto es el log de 16 en base 49
I dont understand why the least common denominator to the problem (3/2x) minus (1/2(x+10)) equals 1 is 2x(x+10)
3u^3-5u^2-2u=0
4x+2y=10
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