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Find out the number of ways in which 5 prizes can be distributed among 5 students such that
(a) Each student may get a prize.
(b) There is no restriction to the number of prizes a student gets. (8)
Ans : (a) Number of ways in which 5 prizes can be distributed between 5 students in such a way that each one may acquire a prize is 5*4*3*2*1 = 5! ways.
(b) While no restriction on the number of prizes a student may get, after that a student may get either 0 or 1 or 2 or...upto 5 prizes. It depicts that a student have six possible ways in which it may get a prize. Hence the number of ways in which prizes can be distributed is 65.
The midpoint of the line joining (2a, 4) and (-2, 3b) is (1, 2a +1).Find the values of a & b. (Ans: a = 2, b = 2) Ans : A(2a, 4) P(1, 2a + 1) B(-2,
IF 7 AND 2 ARE TWO ROOTS OF THE EQUATION |X 3 7 2 X 2 7 6 X |=0 THEN FIND THE THIRD ROOT IS
2 times n times n divided by n
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