Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
If α,β are the zeros of the polynomial 2x2 - 4x + 5 find the value of a) α2 + β2 b) (α - β)2.
Ans: p (x) = 2 x2 - 4 x + 5 (Ans: a) -1 , b) -6)
α + β = -b /a = 4/2 = 2
α β = c/a = 5/2
α2 + β2 = (α + β)2 - 2 α β
Substitute then we get, α 2+ β2 = -1
(α - β)2 = (α + β)2 - 4 α β
Substitute, we get = (α - β)2 = - 6
how do i multiply and divide fractions?
es-335
x 4 - 25 There is no greatest common factor here. Though, notice that it is the difference of two perfect squares. x 4 - 25 = ( x 2 ) 2 - (5) 2 Thus, we can employ
How to Converting Percents to Fractions ? To convert a percent to a fraction: 1. Remove the percent sign. 2. Create a fraction, in which the resulting number from Step 1 is
Solve the subsequent IVP Y'' - 9 y = 0, y(0) = 2, y'(0) = -1 Solution First, the two functions y (t ) = e 3t and y(t ) = e -3t That is "nice enough" for us to
1. a) Find the shortest paths from r to all other nodes in the digraph G=(V,E) shown below using the Bellman-Ford algorithm (as taught in class). Please show your work, and draw t
There are really three various methods for doing such integral. Method 1: This method uses a trig formula as, ∫sin(x) cos(x) dx = ½ ∫sin(2x) dx = -(1/4) cos(2x) + c
An $80.00 coat is marked down 20%. It does not sell, so the shop owner marks it down an additional 15%. What is the new price of the coat? Find out 20 percent of the original p
We have seen that if y is a function of x, then for each given value of x, we can determine uniquely the value of y as per the functional relationship. For some f
one half y minus 14
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd