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Interpretation of the second derivative : Now that we've discover some higher order derivatives we have to probably talk regarding an interpretation of the second derivative.
If the position of an object is specified by s(t) we know that the velocity is first derivative of the position.
v (t ) = s′ (t )
First derivative of any velocity is the acceleration of object; however since it is the first derivative of the position function we can also think of the acceleration as the second derivative of the position function.
a (t ) = v′ (t ) = s′′ (t )
Alternate Notation : There is couple of alternate notation for higher order derivatives. Recall as well that there was a fractional notation for the first derivative.
f ′ ( x ) = df /dx
We should extend this to higher order derivatives.
f ′′ ( x )= d 2 y / dx f ′′′ ( x ) = d 3 y/ dx etc.
Example: Find out a particular solution to y'' - 4y' - 12 y = 3e 5t Solution The point here is to get a particular solution, though the first thing that we're going to
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how to solve this? y = 7x - 12 y = x2 Solve the system using substitution.
1.What are the strengths and shortcomings of the methods of teaching H T 0 in Examples 1 and 2? 2. a) Think of another activity for getting children to practise H T 0, especia
solution for this project
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MATH
Classical Probability Consider the experiment of tossing a single coin. Two outcomes are possible, viz. obtaining a head or obtaining a tail. The probability that it is a tail
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