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Interpretation of the second derivative : Now that we've discover some higher order derivatives we have to probably talk regarding an interpretation of the second derivative.
If the position of an object is specified by s(t) we know that the velocity is first derivative of the position.
v (t ) = s′ (t )
First derivative of any velocity is the acceleration of object; however since it is the first derivative of the position function we can also think of the acceleration as the second derivative of the position function.
a (t ) = v′ (t ) = s′′ (t )
Alternate Notation : There is couple of alternate notation for higher order derivatives. Recall as well that there was a fractional notation for the first derivative.
f ′ ( x ) = df /dx
We should extend this to higher order derivatives.
f ′′ ( x )= d 2 y / dx f ′′′ ( x ) = d 3 y/ dx etc.
A firm buys a product using the price schedule given in the table: The company estimate holding costs at 10% of the purchase price per year and ordering costs at $40 per order .
Tom has five times as many marbles as Jim. together they have 42 marbles. how many marbles does each has?
Finding Absolute Extrema : Now it's time to see our first major application of derivatives. Specified a continuous function, f(x), on an interval [a,b] we desire to find out the
Interpretation of the second derivative : Now that we've discover some higher order derivatives we have to probably talk regarding an interpretation of the second derivative. I
a dairy mngr says it takes 70lbs of make 10 lbs of cottage cheese... How do I make a rate table and a make a graph showing the relationship between lbs of milk and lbs of cottage c
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