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A lotus is 2m above the water in a pond. Due to wind the lotus slides on the side and only the stem completely submerges in the water at a distance of 10m from the original position. Find the depth of water in the pond.
Ans: (x+2)^{2} = x^{2} + 102
x^{2} + 4x + 4 = x^{2} + 100
⇒ 4x + 4 = 100
⇒ x = 24
Depth of the pond = 24m
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