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In order to find the d-orbital splitting in a square planar complex, it is easier to start with an octahedral compound where splitting patterns are known and then imagine slowly moving two trans ligands away from the metal. This would at first distort the molecule which is known as tetragonally distorted octahedron. Moving the ligands further to such an extent I that the interaction between the metal ion and the ligands is practically nil would result in a square planar compound. This situation is best described its square planar complex because the other two ligands are so far off that they can be considered to be unattached to the metal ion and are thus unable to form a true chemical bond.
Number of unpaired electrons in 1s 2 2s 2 2p 3 is: (1) 2 (2) 0 (3) 3 (4) 1 Ans: 3
If hydrogen atom is in an energy level represented by n=4,how many spectral lines are possible in its emission spectrum? Solution) There is a formula for this i.e [ (n 2 - n 1
The diffraction of x-ray by a crystal gives 1st order ref at 14•12'' if lattice dist is 3.14 A• wht is the wavelength of x-ray
Q. Illustrate Law of Equilibrium and Equilibrium Constants? Ans. The general equation for a reversible reaction is given by aA + bB -> cC + dD The law of equilibrium
Acid dyes: These are commonly salts of sulphonic acids and can be helpful to silk, wool and nylon. The presence of sulphonic acid group creates them water soluble. These dyes a
principles of GCMS
A gas contains 350 ppm of H 2 S in CO 2 at 72°F and 1.53 atm pressure. If the gas is liquified, what is the weight fraction H 2 S? You are asked to make up a laboratory soluti
why do s block elements have a weak tendency to fom complexes?
Fission of Covalent bond
Explain relative electronegativities An analysis of relative electronegativities would suggest that, because C is slightly more electronegative than H, a important amount of th
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