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In order to find the d-orbital splitting in a square planar complex, it is easier to start with an octahedral compound where splitting patterns are known and then imagine slowly moving two trans ligands away from the metal. This would at first distort the molecule which is known as tetragonally distorted octahedron. Moving the ligands further to such an extent I that the interaction between the metal ion and the ligands is practically nil would result in a square planar compound. This situation is best described its square planar complex because the other two ligands are so far off that they can be considered to be unattached to the metal ion and are thus unable to form a true chemical bond.
Which of following carbon has sp3 hybriziation for bond formation.??? Ch3,c2h6,(ch3)3cho
principle and explanation of radiometric titration
method of preparation and characteristics of ethane
Which of the following has more unpaired d-electrons: (1) Zn + (2) Fe 2+ (3) N 3+ (4) Cu + An
2NO N2 + O2 has a Keq of 85 Keq = [N2}{02} ------- [NO]2 at equilibrium, would have more reactants or products
why ionisation energy of aluminium is greater then Ga?
chemical properties of dihydrogen
LITHIUM AND BERYLLIUM MARKEDLY DIFFERENT FROM OTHER MEMBERS OF THEIR RESPECTIVE GROUP?.
Phenol + HNO3(in prescence of sulphuric acid) --> 2-nitrophenol + 4-nitrophenol.
what is the function of detectors in hplc?
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