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Let E = xy + y't + x'yz' + xy'zt', find
(a) Prime implicants of E, (b) Minimal sum for E.
Ans: K -map for following boolean expression is given as:
Prime implicant is illustrated as the minimum term which covers maximum number of min terms. In the K-map prime implicant y't covers four (4) min terms. Likewise yz' and xz are other prime implicants. The minimal sum for E is [y't + yz' + xz].
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