Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Find out the surface area of the solid acquired by rotating y = √ (9-x2), - 2 < x < 2 about the x-axis.
Solution
The formula that we'll be using here is,
S = ∫ 2Πyds
As we are rotating about the x-axis and we will make use of the first ds in this case since our function is in the correct form for this reason ds and we won't gain anything by solving it for x. Let us first get the derivative and the root taken care of.
Dy/dx = ½ (9-x2)- ½ (-2x)
= - x / (9-x2)½
√(1+ (dy/dx)2)
= √(1+ x2 / (9-x2))
= √(9 / 9-x2)
= 3/ √(9-x2)
Here's the integral for the surface area,
S = ∫2-2 2Πy (3/ √(9-x2)) dx
Though there is a problem. The meaning of dx here is that we shouldn't have any y's in the integral. Thus, before evaluating the integral we'll require to substitute in for y as well. After that the surface area is,
(x+y+1)dy/dx=1
Question: Find Fourier series for the periodic function of period 2 π,defined by f(x) = x 4 , - π ≤ x ≤ π
Determine if the following sequences are monotonic and/or bounded. (a) {-n 2 } ∞ n=0 (b) {( -1) n+1 } ∞ n=1 (c) {2/n 2 } ∞ n=5 Solution {-n 2 } ∞ n=0
13 1/4 34 56/89
if P is a point in the interior of a triangles ABC,prove that AB>BC+CA
how to find periods in trigon ometry
2
finite or infinite 1]A={4,5,6,....}
can I access algebra videos?
if you have 1/5 of a candy bar and 4 friends how much will they get
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd