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Express the GCD of 48 and 18 as a linear combination. (Ans: Not unique)
A=bq+r, where o ≤ r < b
48=18x2+12
18=12x1+6
12=6x2+0
∴ HCF (18,48) = 6
now 6= 18-12x1
6= 18-(48-18x2)
6= 18-48x1+18x2
6= 18x3-48x1
6= 18x3+48x(-1)
i.e. 6= 18x +48y
∴ x=3 , y=-1
6= 18×3 +48×(-1)
=18×3 +48×(-1) + 18×48-18×48
=18(3+48)+48(-1-18)
=18×51+48×(-19)
6=18x+48y
∴ x = 51, y = -19
Hence, x and y are not unique.
The math equation is written exactly this way: 0+50x1-60-60x0+10=??? The answer I get is 10 and others say 0 0+50=50 50x1=50 50-60=-10 -10-60=-70 -70x0=0 0+10=10
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