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Draw a simple schematic for managing dynamic storage allocation.
A simple schematic for managing dynamic storage allocation is as follows:
Block size pointer
A(code)
A
SA
B(code)
B
SB
C(code)
C
SC
A(data)
Black descriptor table
B(data)
•
A simple schematic for
managing dynamic storage allocation
Free area pointer
Suppose you''re given n numbers and asked to find a number that is greater than or equal to the median a) What is the lower bound for the worst case complexity of this problem?
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How many address bits are required to represent 4K memory ? Ans. 12 address bits are required for representing 4K memory, as 4K = 2 2 x 2 10 = 2 12 Therefore 1K = 1024
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