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A mailbox opening is 4.5 inches high and 5 inches wide. Determine the widest piece of mail able to ?t in the mailbox without bending?
a. 9.5 inches
b. 2.2 inches
c. 6.7 inches
d. 8.9 inches
c. The widest piece of mail will be same to the length of the diagonal of the mailbox. The width, 4.5 in, will be a leg of the right triangle. The height, 5 in, will be other leg of the right triangle. We can solve for the hypotenuse, which is the diagonal of the mailbox, using the Pythagorean theorem; a2 + b2 = c2 or 4.52 + 52 = c2. Solve for c, 20.25 + 25 = c2; 45.25 = c2; c = 6.7. If you select a, you assigned the legs the values of 4.5 and 10; 10 is incorrect. If you select b, you assigned the legs the values of 5 and 10. Again, 10 is incorrect.
a company of 10000 shares of rs 100 each declares a annual dividend of 5 %.what is the total amount dividend paid by the company
Ashow that sec^2x+cosec^2x cannot be less than 4
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How do you solve (17+w)^2 + w^2 = (25+w)^2
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