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A mailbox opening is 4.5 inches high and 5 inches wide. Determine the widest piece of mail able to ?t in the mailbox without bending?
a. 9.5 inches
b. 2.2 inches
c. 6.7 inches
d. 8.9 inches
c. The widest piece of mail will be same to the length of the diagonal of the mailbox. The width, 4.5 in, will be a leg of the right triangle. The height, 5 in, will be other leg of the right triangle. We can solve for the hypotenuse, which is the diagonal of the mailbox, using the Pythagorean theorem; a2 + b2 = c2 or 4.52 + 52 = c2. Solve for c, 20.25 + 25 = c2; 45.25 = c2; c = 6.7. If you select a, you assigned the legs the values of 4.5 and 10; 10 is incorrect. If you select b, you assigned the legs the values of 5 and 10. Again, 10 is incorrect.
limit 0 to 2(3x^2+2) Solution) integrate 3x^2 to x^3 and 2 to 2x and apply the limit from 0 to 2 answer is 12.
1/cos(x-a)cos(x-b)
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how can i memorize the formulas
mr ouma bought two sets of spanners for sh 300per set two machanic vice at sh 1000each three set of screw driver at sh 115 per set and tool box for sh 300
#question.areas of applications of linear program mes to solution to engineering problems.
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