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A rectangular area 4 m × 6 m carries a uniformly distributed load of 100 kN/m2 at the ground surface. Estimate the vertical pressure at a depth of 6 m vertically below the centre and also below a corner of the loaded area. Compare the results with those getting by an equivalent point load method and also by separating the loaded area into four equal parts and treating the load from every as a point load.
State about the pre-tensioned concrete In pre-tensioned concrete, the tendon stresses are transferred to concrete by virtue of bond of concrete to the surface of steel tend
Properties of Ordinary Portland Cement (i) Chemical properties: Portland cement consists chemical compounds are following: (a) Tricalcium silicate 3 CaO.SiO 2 (C
Determine the head loss due to friction using the Darcy-Weisbach equation. The water is pumped at 3.0 gallons per minute, has a temperature of 60 °F and is pumped through a 1inch s
Physical Tests on Cement (a) Soundness Test: by sieve analysis, it is conducted. 100 gms of cement is taken and sieved throughout IS sieve No. 9 for fifteen minutes. Residue on
Example: Convert the following reduced bearings into whole circle bearings: (i) N 65° E (ii) S 43° 15′ E (iii) S 52° 30′ W (iv)
Determine the hydraulic radius R for a rectangular open channel with dimensions of 6 ft wide and 4 ft high (side walls) flowing at a depth of 3 ft. Solution: R = A/P Cross-s
For IRC Class AA loading in existing industrial areas, what is load (kN/m) has to applied base don the wheel loads. especially raft foundation & roads are at same level.
A flitched beam consists of a wooden joist 150 mm wide and 300 mm deep strengthened by steel plates 12 mm thick and 300 mm deep one on either side of the joist. If the maximum st
Guidelines for Selection of Site: The following are some of the guidelines for selecting the site of a bridge : (a) A site which is on a straight reach of the river is pref
Define Dupuit Equations for Unconfined Aquifers Using natural log: Q = ΠK((h 2 ) 2 - (h 1 ) 2 )/ln(r 2 /r 1 ) Using log 10 : Q = K((h 2 ) 2 - (h 1 ) 2 )/((1,055)l
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