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Design volume of the aeration basin - sewer construction:
Problem:
What is the design volume of the aeration basin?
Solution
Assuming that 30% of the plant influent BOD5 is removed during primary sedimentation, this means that So = 444 mg/l × 0.70 = 310 mg/l.
Qc = 1/t
Thus 1/Qc = [(Q0×Y)/(V×X)(S0 - S)] -kd
¼ = [days]=33.75×106 [-1/d]× 55/100[g/g]×(310[mg/l]-2 [mg/l])
V[l]×4300[mg/l]-0.05[1/day]
Solving for V, we get V = 5007558 l = 5,00,000 l.
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