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Design the Synchronous Sequential Circuit for State Diagram
Illustration: - We wish to design the synchronous sequential circuit whose state diagram
The kind of flip-flop to be use is J-K.
Since the state diagram we can generate the state table
Excitation table for JK flip-flop
Excitation table of the circuit
In the first row of Table we have the transition for flip-flop Q0 from 0 in the present state to 0 in the next state. In Table 10 we find that the transition of states from 0 to 0 requires that input J = 0 and input K = X. Thus 0 and X are copied in the first row under J0 and K0 respectively. Ever since the first row also shows a transition for the flip-flop Q1 from 0 in the present state to 0 in the next state 0 and X are copied in the first row under J1 and K1 and this process is continued for each row of the table and for each flip-flop.
The simplified Boolean functions for a combinational circuit can now be derived. The input variables are Q0, Q1, and x and the output is the variables J0, K0, J1 and K1 and the information from the truth table is plotted on the Karnaugh maps.
For the circuit shown in Figure, use KCL and KVL to determine i 1 , i 2 , v bd and v x . Also, find v eb .
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