Compute the thermal stresses in steel, Civil Engineering

Assignment Help:

Compute the thermal stresses in steel:

Consider the compound bar shown in below figure consisting of a steel bolt of diameter 18 mm, surrounded through a copper tube of outer and inner diameters 30 mm and 18 mm respectively. The assembly is just snug at 15oC. The material properties are given as:

Young's modulus of steel, ES = 200 kN/mm2

Young's modulus of copper, EC = 120 kN/mm2.

Coefficient of linear thermal expansion of steel, αs  = 12 × 10-6  m/m/ o C

Coefficient of linear thermal expansion of copper, αc  = 18 × 10-6  m/m/ o C

Compute the thermal stresses in steel and copper when the temperature of the assembly is raised to 45oC.

1806_Compute the thermal stresses in steel.png

Figure

Solution

In this case, when the temperature of the assembly is raised, copper will expand more than steel and hence, will exert a thrust on the steel nut and bolt head thus producing tension in the steel. Since there is no other external force this tension has to be kept in equilibrium by the compressive force induced in copper. Hence by formulating a compatibility condition of total strains (thermal + elastic) the problem could be solved.

Now let the forces induced in steel and copper are designated as Ps and Pc respectively in kN units.

Thermal strain in steel, εst  = αs  × ΔT

= 12 × 10-6 × (40 - 15)

= 3 × 10-4 m/m

Thermal strain in copper, αc  × ΔT

= 18 × 10-6 × (40 - 15)

= 4.5 × 10-4 m/m

Elastic strain in steel,  δse  = Ps /As Es

=          Ps/ (π/4) × 182 × 200

= 1.965 × 10-5 Ps

Elastic strain in copper, δce = Pc /Ac Ec

=          Pc/ (π/4) × (302 - 182) 120

= 1.8421 × 10-5 Pc


Related Discussions:- Compute the thermal stresses in steel

Block contouring, how to calculate contour surveyed area

how to calculate contour surveyed area

Strength of materials, An I-section beam 350*200mm2 has a web thickness of ...

An I-section beam 350*200mm2 has a web thickness of 12.5mm & a flange thickness of 25mm. It carries a shearing force of 200KN at a section. Sketch the shear stress distribution acr

Cumulative error, diffrence between cumilative compensative error

diffrence between cumilative compensative error

Explain flocculation, Explain Flocculation Most important factor ef...

Explain Flocculation Most important factor effecting particle removal efficiency objective - to bring particles into contact so that they will collide, stick together

Determine the strain compatibility method, Determine the Strain Compatibili...

Determine the Strain Compatibility method For estimating the ultimate strength of prestressed concrete members in flexure, 'Strain Compatibility method' may be used. For calcul

Ballast and sub-ballast aggregates, I want to check the grammer of report a...

I want to check the grammer of report and edit it in better sentances , reduce the Plagiarism & edit the reference to havaerd style

Grillage foundation, what are the advantages of grillage foundation and why...

what are the advantages of grillage foundation and why people prefers that?

What are rules for working of dip lorries, Q. What are rules for working of...

Q. What are rules for working of Dip lorries and their protection arrangements on a single line section explain with sketches? Ans.-Rules for working of Dip lorries - i. Sub

Rubber dams – air-filled vs water-filled, Most of the existing rubber dams ...

Most of the existing rubber dams are of air-filled types. Water-filled rubber dams aren't preferred for the below reasons: (i)  By giving same sheet length and dam height, tensi

Sway porta frame, how to sway portal frame both end fixed due to eccentric ...

how to sway portal frame both end fixed due to eccentric loading with diagram

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd