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Q. In an ideal transformer, the transformer ratio is 1:20.The input voltage and the input power are 6 V and 600 mW respectively. Compute the primary and the secondary currents.
Solution:
EpIp = 600 mW = 600 X 10-3 W
Primary current Ip = EpIp / Ep = 600 X 10-3/ 6 = 100 X 10 -3A
Ip / Is = 1 /20
Secondary current is = Ip X 20 = 2000 X 10 -3 A = 2 A
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