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A body of mass m1 , moving with velocity u1 collides head on with a body of mass m2 moving with a velocity u2 the two bodies stick together after the collision the loss of kinetic energy after the collision is ?Ans) Initial KE of the system= 1/2 [ m1.u1^2 + m2.u2^2 ]applying conservation of momentum we get new velocity of the new body= (m1.u1-m2.u2) / (m1+m2)new KE of the Body= [ (m1.u.1 - m2.u2) / 2.(m1+m2) ]^2Subtracting and simplyfing we get the loss in KE after Collision= [ m1.m2. (u1 + u2)^2 ] / [ 2.(m1 + m2) ]
A CAR MOVING AT 25m/s ALONG A STRAIGHT LEVEL ROAD EXPERIENCE A RESISTANCE WHICH PRODUCES A RETARDATION OF 0.0001 V^3,WHERE V IS THE VELOCITY IN m/s.FIND THE DISTANCE TRAVELLED AND
The charged particles whose flow in a exact direction constitutes the electric current are known as current carriers. In separate positions current carriers are dissimilar. (i)
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True or False. The specific gravity of a fluid that sinks in water is greater than 1.00.
Define the terms threshold frequency and stopping potential in relation to the phenomenon of photoelectric effect. How is the photoelectric current affected on enhancing the (i)
What is balance and equilibrium?
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A wooden ring stand The bottom for this ring stand is made from a piece of wood 40 cm long, 15 cm wide and 1 cm thick. A whole 1 cm in diameter is bored by the centre of the ba
Since the objects stick together they will be a part of plastic collision...so. conservation of kinetic energy cannot be applied...Apply conservation of linear momentum and then find individual velocitiesthen loss of kinetic energy will be change in kinetic energy......So,it will become equal to amount of work done.
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