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Compare the memory devices RAM and ROM.
Ans. Comparison of Semi-conductor Memories RAM ands ROMThe advantages of ROM are:1. This is cheaper than RAM.2. This is non-volatile. Thus, the contents are not lost while power is switched off.3. This is available in larger sizes than RAM. '4. Contents these are always identified and can be easily tested.5. This does not need refreshing.6. There is no option of any accidental change into its contents.The advantages of RAM are:1. This can be replaced and updated.2. This can serve as temporary data storage.3. This does not need lead time (like in ROM) or programming time (like in PROM).4. This does not need any programming equipment
Explain Non-Folded network Non-Folded Network: In a switching network, every inlet/outlet connection may be utilized for inter exchange transmission. In this case, the .excha
What is slack? 'Slack' is the amount of time you have which is measured through while an event ‘really happens' and while it ‘should happen’. The term ‘really happens' can a
Write a ‘C’ functions to arrange the elements of an integer array in such a way that all the negative elements are before the positive elements. The array is passed to it as an arg
Quality of Service: This is assessed on the basis of customer's satisfaction.
Q. What is CODE SEGMENT? The logical program segment is termed as code segment. When linker links a program it makes a note in header section of program's executable file defin
What is pipelining? The overlapping of implementation of successive instructions is known as pipelining.
Multithreading is the process in which more than single thread run independent of each other within the process in any programming language such as C, C++, etc.
Give explanation about the use of SSL to secure the network. SS L stands for Secure Sockets Layer is a protocol developed through Netscape for transmitting private document
What is time multiplexed space switching? Explain w ith a neat diagram. Time division switches, an inlet or an outlet corresponded to a particular subscriber line with one s
Simulated Annealing: One way to get around the problem of local maxima, and related problems like ridges and plateaux in hill climbing is to allow the agent to go downhill to
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