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Compare Procedure & Macro
Accessed by CALL & RET instruction Accessed during assembly with name given during program implementation to macro when defined Machine code for instruction is put only once in the memory Machine code is generated for instruction each time when macro is called With procedures less memory is needed With macro more memory is needed Parameters can be passed in registers, memory locations or stack
Parameters passed as part of statement which calls macro
Op code Format As we have seen in the section that the first byte of all the instruction is the op code. microprocessors reads this op code and decodes it to identif
Explain Acceptance cone? The fibre air - core interface is display below: In this figure Omax is the maximum angle, inside that the rays undergo total internal reflecti
Factors Affecting Choice of Observation: Observers are influenced by a number of factors in the process of observation. Black and champion have identified three such factors.
Q. Explain Time-Dependent Circuit Analysis? The response of networks to time-varying sources is considered in this chapter. The special case of sinusoidal signals is of particu
Q. Consider the magnetic circuit shown in Figure. Assume the relative permeability of the magnetic material to be 1000 and the cross-sectional area to be the same throughout. Deter
The Central Processing Unit The central processing unit is the brain of whole PLC. The CPU consist of a microprocessor memory chip and other integrated circuits to con
The material with lowest resistivity is (A) Constantan. (B) Silver. (C) manganin. (D) nichrome. Ans: The material with lowest resist
The Octal Inverter 74LS 240 It is similar to above octal buffer but with inverter output. The logic diagram is shown in figure below . Normal 0
Q. Amplifiers with Feedback? Almost all practical amplifier circuits include some form of negative feedback. The advantages gained with feedback may include the following: •
Q. In the ideal inverting summing amplifier circuit with two inputs, for R f = 10 k, find R 1 and R 2 so that v o = -10v i1 -5 vi2 .
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