Measure phase angle by using an oscilloscope, Electrical Engineering

Assignment Help:

1. Introduction:

Theory:  Phase angle is defined as the number of degrees separating two sine waves of the same frequency. The Phase shift is defined as any change that occurs in the phase of one quantity, or in the phase difference between two or more quantities.

For infinitely long sinusoids, a change in Θ is the same as a shift in time, such as a time-delay.  If x (t) is delayed (time-shifted) by 1/4   of its cycle, it becomes:

1070_measure phase angle by using an oscilloscope.png

whose "phase" is now  Θ- (Π / 2)  It has been shifted by (Π / 2) radians.

Material Required: Oscilloscope, frequency generator, connecting wires, resistor, capacitor, potentiometer, multimeter.

Description and Aim: To measure phase angle by using an oscilloscope. The phase angle between two waveforms is calculated by ensuring that they are of same frequency. The amplitude can differ for both these waveforms. An input waveform will be passed through circuit which may make some changes in the phase of this waveform. Hence, the phase angle between the input and output waveforms is measured using the oscilloscope where one channel displays the reference waveform and other channel displays the second signal.

2. Method:

Step 1) First, make a circuit using a capacitor and a resistor. The potentiometer can also be used and turn it fully otherwise. The capacitor creates a phase shift in the waveform passing through it.

Step 2) Connect generator to phase angle circuit block. Using an oscilloscope, set generator for a sine wave output 6Vpk-pk at 1000 Hz.

Step 3) Connect channel 1 probe to input of the generator and channel 2 probe to output across C1. Ensure that oscilloscope trigger source control is set to channel 1. Switch from the vertical mode to ALT. Set ground references of both the channel to the graticule line. The phase angle between channel 1 and channel 2 is approximately zero at this moment.

Step 4) Slowly turn the potentiometer R2 completely clockwise. It makes the phase shift to right direction.

Step 5) Switch vertical mode to channel 1 and adjust time base and variable time base controls on oscilloscope so that one cycle of waveform is having exactly 8 divisions.

Step 6) Calculate phase angle between the two waveforms.

3. Results:

Frequency of waveform = 1000 Hz

V(pk-pk) = 6V

No of horizontal divisions for one cycle of waveforms = 8

Measure of one division = 45°

Phase angle  = 8 X 45° /  5  = 360° / 5   = 72°

(how did u get 5 in above line...mention that here)

4. Discussion:

Phase measurement of a waveform using oscilloscope is done. Prime source of error is resolution error, which is reduced by ensuring phase crossings align with ticks of oscilloscope.  If this experiment needs to be repeated for higher frequencies time step has to be properly changed to avoid quantization error.


Related Discussions:- Measure phase angle by using an oscilloscope

Calculate the induced voltage, Q. A four-pole, lap-wound armature has 144 s...

Q. A four-pole, lap-wound armature has 144 slots with two coil sides per slot, each coil having two turns. If the flux per pole is 20 mWb and the armature rotates at 720 r/min, cal

New asic design flow, There is a requirement to propose a new ASIC design f...

There is a requirement to propose a new ASIC design flow within your company, from VHDL design capture through to GDSII tape out.  It is very important that the flow includes all t

Integrated circuit with resistive feedback, principle of resistive feedback...

principle of resistive feedback circuit change when the square wave and triangular pulse frequencies, the amplitude of the triangle wave

Distinguish between ferromagnetic and diamagnetic materials, Distinguish be...

Distinguish between ferromagnetic and diamagnetic materials, mentioning at least one example of each. Ferromagnetic Materials: These are materials wherein magnetic dipoles in

Explain demodulation of dsb, Q. Explain Demodulation of DSB? Demodulati...

Q. Explain Demodulation of DSB? Demodulation of DSB SC AM signals requires a synchronous demodulator, which is also known as coherent or synchronous detector. That is, the demo

Read-and-write memory, Q. Read-and-write memory? Writing is the same as...

Q. Read-and-write memory? Writing is the same as storing data intomemory and reading is the same as retrieving the data later. RAM is said to be volatile because its contents a

Power and power distribution, design a single phase distribution circuit fr...

design a single phase distribution circuit from a supply point to a load

Calculate efficiency to load at unity power factor, Q. A 300-kVA transforme...

Q. A 300-kVA transformer has a core loss of 1.5 kW and a full-load copper loss of 4.5 kW. (a) Calculate its efficiency corresponding to 25, 50, 75, 100, and 125% loads at unity

Write short note on a negative clamper, Q. Write short note on a negative c...

Q. Write short note on a negative clamper ?   A circuit which places the negative peak of a signal at a desired level is known as a negative clamper (1). During the

Advantages of high level languages , Advantages of High  level  Languages...

Advantages of High  level  Languages a.It is  easy  to learn  write and debug  the program  written in high  level  languages. b.Programs are more  legible as compared to m

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd