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CBW: Convert Signed Byte to Word: This instruction converts a signed byte to a signed word. In other terms, it copies the sign bit of a byte to be converted to all of the bits in the higher byte of the result word. The byte to be converted might be in the AL. The result will be stored in the AX. It does not affect any flag.
CWD: Convert Signed Word to Double Word: This instruction copies the sign bit of the AX register to all the bits of the DX register. This operation is to be done before signed division. It does not make affect on any flag.
Flag Register : 8086 has a 16-bit flag register which is divided into 2 parts, viz. (a)machine control flagsand (b)condition code or status flags. The condition code flag regi
1. The microwave has a clock (hh:mm:ss am/pm) and the user should be able to change the clock at any time. 2. For cooking the user should first enter the time. The user can ente
Comparison between 8086 and 8088 All the changes in 8088 above 8086 are indirectly or directly related to the 8-bit, 8085 compatible data and control bus interface. 1) The p
I/O interface I/O devices such as displays and keyboards establish communication of computer with outside world. Devices may be interfaced in 2 ways Memory mapped I/O and I/
Linking a program The DOS linking program LINK.EXE links the different object modules of function library routines and source program to produce an integrated executable code o
Request a depreciation of the item, year of purchase, cost of item, number of years to be depreciated (estimated life ) and,the method of depreciation . Method of depreciation sh
I need a division subroutine. Asks for two inputs, then displays the inputs and shows the answer with a remainder. Mine isnt displaying the inputs correctly.
Memory Segmentation : The memory in an 8086/8088 based system is organized as segmented memory. In this scheme, the whole physically available memory can be divided into a n
There are 3 kinds of OCWs. The command word OCWI is utilized for masking the interrupt requests; when the mask bit corresponding to an interrupt request is value 1, then the requ
Assembly Language: Inside the 8085, instructions are really stored like binary numbers, not a very good manner to look at them and very difficult to decipher. An assembler is
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