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Program :
Write an assembly program to find out the number of positive numbers and negative numbers from a given series of signed numbers.
Solution :
Take the ith number in any of the registers. And rotate it left throughout carry. The status of carry flag, for example the most significant bit of the number will give the information regarding the sign of the number. If CF is 1, the number is negative; or else, it is positive.
Pin functions for the minimum mode operation of 8086 are following: 1) M/I/O -Memory/IO: This is a status line logically equivalent to S2 in maximum mode. When it is low, it
Write an application that does the following: (1) fill an array with 50 random integers; (2) loop through the array, displaying each value, and count the number of negative values;
Interrupt When the CPU detects an interrupt signal, it stops activity of current and jumps to a special routine, known an interrupt handler. This handler then detects why the i
INC: Increment : - This instruction increments the contents of the particular memory or register location by the value 1. All the condition code flags are affected except the carry
Declare 1 constant. This can be done just below the prototype section. Put the following divider above the constant section. ;************************ Constants ****************
#include"lcd.asm" ; assembly file is included for displaying lcd characters Main: PORTA EQU 0xF80 ; PORTS PORTB EQU 0xF81 PORTC EQU 0xF82 PORTD EQU 0xF83 R
errorlevel -302 ;prevents error code for this chipset __config 0x373A ;chip config PIC spec page 146 processor 16F877A ;chipset reset code
The definitions of the bits in ICWI are following: Always set to the value 1. It directs the received byte to ICWI as oppose to OCW2 or OCW3. Which also utilize the even addr
Read Architecture: Look Through Main memory that located is conflicting the system interface. The least concerning feature of this cache unit is that it remain between the proc
Flowchart for the sequence of 8251 Whether the control, mode or sync character register is selected depends on the accessing sequence. A flowchart of the sequencing is given i
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