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Ans)
You can integrate tanθ
write tanθ=sinθ/cosθso now, integral of tanθ.dθ=integral of sinθ/cosθ.dθ→1put cosθ=t→2there fore -sinθ.dθ=dt→3put 2 and 3 in 1so,the question becomes integral of tanθ.dθ=integral of -dt/t→4=-log t +c → 5 [reason:dx/x=logx]put 2 in 5, =-log cosθ+Cwhere C is the integration constant
how do u add and subtract integers
David invests $17,000 into an account and at the end of 7 years, his account has a balance of $ 26,417.77. What is the interest rate (assuming annual compounding)?
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5 2 ----- - ----- x-1 x+1 -------------------- x 1 ----- + ----- x-1 x+1
Hi, I don''t know how to solve 2(5x+3)
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I cant figure out how to study for my math test
how do u add them together?
If the minute hand of a big clock is 1.05 m long, find the rate at which its tip is moving in cm per minute.
yes you can intergrate tan θ tan q = sin q/cos q (1) let, y = cos q so, dy/dq = -sin q this implies, dq=dy/-sin q (2) putting values in (1) ∫ 1/-y = -log|y| =-log|cos q| so the ∫ tan q = -log|cos q|
yes you can intergrate tan θ
tan q = sin q/cos q (1)
let,
y = cos q
so, dy/dq = -sin q
this implies, dq=dy/-sin q (2)
putting values in (1)
∫ 1/-y
= -log|y|
=-log|cos q|
so the ∫ tan q = -log|cos q|
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