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Can copy constructor admit an object of the same class as parameter, rather than reference of the object?
write a program which has three classes
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Problem : Change to palindrome A palindrome is a string that reads the same from both the ends. Given a string S convert it to a palindrome by doing character replacement. Your ta
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Raj is a newbie to the programming and while learning the programming language he came to know the following rules: · Each program must start with ''{'' and end with ''}''
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A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concate program 1 : package test
A: No. this is specified in the definition of the copy constructor itself. It must generate an error if a programmer specifies a copy constructor along a first argument that is an object and not a reference.
constructor with a single argument creates that constructor as conversion ctor and it can be utilized for type conversion. For instance: class Boo { public: Boo ( int i ); }; Boo BooObject = 10; // assigning int 10 Boo object
constructor with a single argument creates that constructor as conversion ctor and it can be utilized for type conversion.
For instance:
class Boo
{
public:
Boo ( int i );
};
Boo BooObject = 10; // assigning int 10 Boo object
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