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Can copy constructor admit an object of the same class as parameter, rather than reference of the object?
6999066263304447777077766622337778 -----> message sent by the first smuggler. my name is robert---------> message decoded by the second smuggler. Where ‘0’ denotes the "space".
Can I drop the [] while deleteing array of some built-in type (char, int, etc)? A: No. you can't Sometimes programmers think that the [] in the delete[] p only present so the
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algorithm to find out all the factors of given positive integers
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A: No. this is specified in the definition of the copy constructor itself. It must generate an error if a programmer specifies a copy constructor along a first argument that is an object and not a reference.
constructor with a single argument creates that constructor as conversion ctor and it can be utilized for type conversion. For instance: class Boo { public: Boo ( int i ); }; Boo BooObject = 10; // assigning int 10 Boo object
constructor with a single argument creates that constructor as conversion ctor and it can be utilized for type conversion.
For instance:
class Boo
{
public:
Boo ( int i );
};
Boo BooObject = 10; // assigning int 10 Boo object
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