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Can copy constructor admit an object of the same class as parameter, rather than reference of the object?
Operation on array: void Array::add( Object& toAdd ) { lastElementIndex++; while( ptrAt( lastElementIndex ) != ZERO && lastElementIndex
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how yo use the friend function?
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Hiding overloaded functions We cannot overload a base class function by redefining it in a derived class with a dissimilar argument list. Consider examples to see if similar fu
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A: No. this is specified in the definition of the copy constructor itself. It must generate an error if a programmer specifies a copy constructor along a first argument that is an object and not a reference.
constructor with a single argument creates that constructor as conversion ctor and it can be utilized for type conversion. For instance: class Boo { public: Boo ( int i ); }; Boo BooObject = 10; // assigning int 10 Boo object
constructor with a single argument creates that constructor as conversion ctor and it can be utilized for type conversion.
For instance:
class Boo
{
public:
Boo ( int i );
};
Boo BooObject = 10; // assigning int 10 Boo object
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