Calculate the actual machining time, Mechanical Engineering

Assignment Help:

Calculate the Actual Machining Time

Estimate the actual machining time required for the component of diameter 42 mm and length 120 mm. The available speeds are 70, 110, 176, 280, 440, 700, 1100, 1760 and 2800. Use a roughing speed of 30 m/min and finish speed of 60 m/min. the feed roughing is 0.24 mm/rev. while that for finishing is 0.10 mm/rev. The maximum depth of cut for roughing is 2 mm. Finish allowance might be taken as 0.75 mm. Blank to be utilized for machining is 50 mm in diameter.

Solution

Stock to be removed = (50 - 42)/4 = 4 mm

Finish allowance = 0.75 mm

Roughing

Stock available = 4 - 0.75 = 3.25 mm

Since maximum depth of cut to be taken is 2 mm, there are two roughing passes.

Given cutting speed V = 30 m/min

Average depth of cut = (50 + 42)/2 = 46 mm

Spindle speed N = (1000 × 30) / (π× 46) = 207.59 rpm

The nearest rpm available from the list is 176 rpm as 280 is very high compared to 207 as calculated.

Machining time for one pass =(120 + 2) / (0.24 × 176) = 2.898 minutes

Finishing

 Given cutting speed V = 60 m/min

 Spindle speed N = (1000 × 30)/ (π× 42)  = 439.05 rpm

The nearest rpm available from the list is 440 rpm

Machining time for one pass = (120 × 2 )/ (0.10 × 440)

                                                  = 2.77 minutes

Total machining time = 2 × 2.888 + 2.77 = 8.546 minutes


Related Discussions:- Calculate the actual machining time

General resource models, General Resource Models In  computer  control...

General Resource Models In  computer  controlled scheduling,    material,  machine handling  equipment,  tooling  and  buffer  space  should  be comprised. The explicit consid

Borides, Borides Borides of Mo, W, Cr, Ti and Zr find extensive indust...

Borides Borides of Mo, W, Cr, Ti and Zr find extensive industrial application. They exhibit extremely high hardness, melting point from 1800 to 3000 o C and good chemical resi

Magnetic field system employed in electromechanical devices, Q.   Why are m...

Q.   Why are magnetic field system employed in practical electromechanical energy conversion devices rather than electric field systems? Ans. In case of magnetic field sys

By ansys finite element discuss the states of stress, A loaded structural c...

A loaded structural component, shown in Fig Q7, is manufactured from sheet steel having a Young's modulus, E = 208000 MPa and a Poisson's ratio, n = 0.3. The sheet steel is 2 mm th

Painting of structural components of skid, Q. Painting of structural compon...

Q. Painting of structural components of skid? Sandblasting and priming shall be carried out prior to assembly, and shall include all bolt holes, flange faces, etc. Flange gaske

Find out the number of revolution, Find out the number of revolution: ...

Find out the number of revolution: A flywheel of mass 20 kg and radius 100 mm is made to rotate at 600 RPM. Determine the KE of the flywheel. If the frictional couple at its b

Automatic feature recogniton system, I have been tasked to design a web bas...

I have been tasked to design a web based automatic feature recognition system for a press brake bending machine, how do I go about It?

Evaluate stress in fibre, Evaluate stress in fibre: Example, the matri...

Evaluate stress in fibre: Example, the matrix material can be stressed to its full strength of 80 MPa, calculate the allowable % of broken fibres. What will be the stress in f

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd