Calculate the actual machining time, Mechanical Engineering

Assignment Help:

Calculate the Actual Machining Time

Estimate the actual machining time required for the component of diameter 42 mm and length 120 mm. The available speeds are 70, 110, 176, 280, 440, 700, 1100, 1760 and 2800. Use a roughing speed of 30 m/min and finish speed of 60 m/min. the feed roughing is 0.24 mm/rev. while that for finishing is 0.10 mm/rev. The maximum depth of cut for roughing is 2 mm. Finish allowance might be taken as 0.75 mm. Blank to be utilized for machining is 50 mm in diameter.

Solution

Stock to be removed = (50 - 42)/4 = 4 mm

Finish allowance = 0.75 mm

Roughing

Stock available = 4 - 0.75 = 3.25 mm

Since maximum depth of cut to be taken is 2 mm, there are two roughing passes.

Given cutting speed V = 30 m/min

Average depth of cut = (50 + 42)/2 = 46 mm

Spindle speed N = (1000 × 30) / (π× 46) = 207.59 rpm

The nearest rpm available from the list is 176 rpm as 280 is very high compared to 207 as calculated.

Machining time for one pass =(120 + 2) / (0.24 × 176) = 2.898 minutes

Finishing

 Given cutting speed V = 60 m/min

 Spindle speed N = (1000 × 30)/ (π× 42)  = 439.05 rpm

The nearest rpm available from the list is 440 rpm

Machining time for one pass = (120 × 2 )/ (0.10 × 440)

                                                  = 2.77 minutes

Total machining time = 2 × 2.888 + 2.77 = 8.546 minutes


Related Discussions:- Calculate the actual machining time

Evaluate the work done by the gas during the expansion, (a) What do you und...

(a) What do you understand by the following : (i) Open System (ii) Closed System (iii) Concept of ‘Work' (b) 0.014 m 3 gas at a pressure of 2070 KPa expends to a pressure of

Determine the maximum shear stress, Determine the maximum shear stress: ...

Determine the maximum shear stress: A beam of triangular cross section of base width 120 mm & height 80 mm is subjected to a shear stress force of 3 kN. Determine the maximum

Calculate resonant frequency, A vibrating system having mass 1.2 Kg is susp...

A vibrating system having mass 1.2 Kg is suspended by a spring of stiffness 1000 N/m and it is put to harmonic excitation of 10 N. Assuming viscous damping, Calculate : (a) R

Alignment of piping flanges, Q. Alignment of piping flanges? Alignment ...

Q. Alignment of piping flanges? Alignment of piping flanges shall be in accordance with ASME B16.5. This code specifies that: • Flange centerline misalignment must be within

Describe term pattern materials, Pattern Materials The requirements of ...

Pattern Materials The requirements of pattern are: Secure the desired shape and size of the casting. Cheap and readily available. Light in mass and convenient to

Compound shaft, Compoun d shaft: compoun d shaft? How is compound ...

Compoun d shaft: compoun d shaft? How is compound shaft classified?                                                               Sol.: Shaft made up of 2 or more mat

Metallurgy, what is mean by precipitation hardening?

what is mean by precipitation hardening?

Cutting technology., can you explain about merchant circle,cutting forces

can you explain about merchant circle,cutting forces

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd