Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
We can also use the logical operators to numbers directly and perform simple bit manipulation . The operators are
& Bitwise AND | Bitwise OR ^ Bitwise exclusive or ~ Bitwise one's complement i.e. NOT << Left shift >> Right shift
Example A 8 bit number represents a coded function, bit 3-4 describes the operation to be performed on the number in bits 0- 2 and 5-7 the function i.e. 00 Add 01 Subtract 10 Divide 11 Multiply Write a Program to extract the number and operation
Answer We need to extract the bits 3-4, the answer is bit operators Assume number is in the variable A i.e. 11011011 Mask off the first number i.e. bit 0-2 num1 = a & 0x07; 11011011 and 00000111 00000011 Mask off the second number i.e. bit 5 -7 num2 = a & 0xe0; 11011011 and 11100000 11000000 We need to shift num2 down by 5 places i.e. num2 = num2 >>5; 00000110
This could be done in one instruction i.e. num2 = (a & 0xe0) >> 5; Mask off the operation bits i.e. bit 4-5 operation = (a & 0x18) >> 3; We can then use the switch statement to select each operation switch(operation) { case 0: total = num1+num2; break; case 1: total = num1-num2; break; case 2: total = num1/num2; break; case 3: total = num1*num2; break; } Hence the entire program is #include void main() { char prompt; /*Author : Mr James Mc Carren Company: Staffordshire University Date: 26th August 2012 Version 1.0 Function : To show bit manipulation Modifications: none*/ int num1,num2,operation,total,a; printf("Please enter in the number\n\r"); scanf("%x",&a); num1 = a & 0x07; num2 = (a & 0xe0) >> 5 ; operation = (a & 0x18) >> 3; switch(operation) { case 0: total = num1+num2; break; case 1: total = num1-num2; break; case 2: total = num1/num2; break; case 3: total = num1*num2; break; } printf("The total is %d\n\r",total); printf("Press and key to exit \n\r"); scanf("\n%c",&prompt); }
Memory Organization - Computer architecture: BASIC CONCEPTS: Address space - 16-bit : 216 = 64K mem. locations - 32-bit : 232 = 4G mem. locations - 40-b
What is pipelining? What are the various hazards encountered in pipelining? Explain in detail. The major characteristics of a pipeline are: a) Pipelining cannot be exe
PCI bus transactions: PCI bus traffic is prepared of a series of PCI bus transactions. Each transaction is build up of an address phase that is followed by 1 or more data phas
Q. Define Interrupts and Instruction Cycle? Let's precise the interrupt process, on the event of an interrupt, an interrupt request (in form of a signal) is concerned to CPU. T
What are the server specific middle wares? Server specific middle wares. Their role in e-commerce. Additional features needed by e-commerce server. Middleware is the term of
A 6-bit Dual Slope A/D converter uses a reference of -6V and a 1 MHz clock. It uses a fixed count of 40 (101000). Find Maximum Conversion Time. Ans. The time T 1 specifie
Q. What are Dynamic Process Groups? To create and manage dynamic groups a separate library libgpvm3.a should be linked with the user programs which make use of any of group fun
draw circuit diagram and the truth table that represent demultiplexer
Boolean algebra. Boolean algebra mathematical method based on human reasoning. In Boolean algebra only two states exist; true and false which are written as 1 (true) and 0 (fa
Channel means logical communication link. There are two parts of channels a) Message channel, b) MQI channel 1) Mesage channel use for communication among QMgr to Q
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd