Bit manipulation techniques, Computer Engineering

Assignment Help:

  We can also use the logical operators to numbers directly and  perform simple bit manipulation . The operators are

    &  Bitwise AND
    |  Bitwise OR
    ^  Bitwise exclusive or 
    ~  Bitwise one's complement i.e. NOT
    <<  Left shift
    >>   Right shift

Example
  A 8 bit number represents a coded function, bit  3-4 describes the operation to be performed on the number in bits 0- 2 and 5-7  the function i.e. 
 
    00    Add
    01    Subtract
    10     Divide
    11    Multiply
 
  Write a Program to extract the number and operation

Answer
We need to extract the bits 3-4, the answer is bit operators 
 
    Assume number is in the variable A i.e.  11011011
 
    Mask off the first number i.e. bit 0-2
    num1 = a & 0x07;        11011011 and
                00000111
                00000011
    
    Mask off the second number i.e. bit 5 -7
    num2 = a & 0xe0;        11011011 and
                11100000
                11000000
 
    We need to shift num2 down by 5 places i.e.
    num2 = num2 >>5;
                00000110

This could be done in one instruction i.e.
    num2 = (a & 0xe0) >> 5;
 
  Mask off the operation bits i.e. bit 4-5
    operation = (a & 0x18) >> 3;
 
  We can then use the switch statement to select each operation
  switch(operation)
  {
  case 0:  
    total = num1+num2;
    break;
  case 1: 
     total = num1-num2;
    break;
  case 2:  
    total = num1/num2;
    break;
  case 3:  
    total = num1*num2;
    break;
  }
Hence the entire program is 
  #include
  void main()
  { 
  char prompt;
  /*Author : Mr James Mc Carren 
  Company: Staffordshire University 
   Date: 26th August 2012 
  Version 1.0 
   Function : To show bit manipulation
   Modifications:   none*/
  int num1,num2,operation,total,a;
  printf("Please enter in the number\n\r");
  scanf("%x",&a);
  num1 = a & 0x07;  
  num2 = (a & 0xe0) >> 5 ;
  operation = (a & 0x18) >> 3;
  switch(operation)
  {
  case 0:   total = num1+num2;
    break;
  case 1:  total = num1-num2;
    break;
  case 2:  total = num1/num2;
    break;
  case 3:  total = num1*num2;
    break;
  }
  printf("The total is %d\n\r",total); 
  printf("Press and key to exit \n\r");
  scanf("\n%c",&prompt);
  }


Related Discussions:- Bit manipulation techniques

De morgans laws, De Morgan's Laws : With continuing the relationship b...

De Morgan's Laws : With continuing the relationship between ^ and ? , we can also needs De Morgan's Law to rearrange sentences involving negation in conjunction with these con

Explain parameter passing in procedures, Q. Explain Parameter Passing in Pr...

Q. Explain Parameter Passing in Procedures? Parameter passing is a very vital concept in assembly language. It makes assembly procedures more general. Parameter can be passed t

What are the applications of edi in business, What are the applications of ...

What are the applications of EDI in business A.  Organistions that use EDI Extensive users of EDI contain: BHS- is a UK and European retailer dealing majorly in appare

Bus master - computer architecture, Bus Master: In  computer system,  ...

Bus Master: In  computer system,  bus  mastering  is  a attribute  supported  by  various  bus  architectures  that  enables  a  device linked to the bus to initiate transacti

How steps of instruction execution can be broken down, Q. How steps of inst...

Q. How steps of instruction execution can be broken down? Let's explain how these steps of instruction execution can be broken down to micro-operations. To make easier this dis

State of the register, What is the state of the register in Figure  after e...

What is the state of the register in Figure  after every clock pulse if it begins in the 101001111000 state?

How can we access the correction and transport system, How can we access th...

How can we access the correction and transport system? Each time you make a new object or change an existing object in the ABAP/4 Dictionary, you branch automatically to the W

Explain about indexed addressing scheme, In this technique, operand field o...

In this technique, operand field of instruction includes an address and an index register thatcomprises an offset. This addressing scheme is normally used to address the consecutiv

How many select lines will have a 16 to 1 multiplexer, How many select line...

How many select lines will a 16 to 1 multiplexer will have ?   Ans. For 16 to 1 MUX four select lines will be needed to select 16 (2 4 ) inputs.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd