binary search tree, Data Structure & Algorithms

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write an algorithm to delete an element x from binary search with time complex

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Define doubly linked list, A list item stores pointers and an element ...

A list item stores pointers and an element to predecessor and successor. We call a pointer to a list item a handle . This looks simple enough, but pointers are so powerful tha

Hash table, Programming for hash table?

Programming for hash table?

Define heap, HEAP  A heap is described to be a binary tree with a key i...

HEAP  A heap is described to be a binary tree with a key in every node, such that  1-All the leaves of the tree are on 2 adjacent levels. 2- All leaves on the lowest leve

Balance theorem, Question 1 Discuss the following theorems with respect to...

Question 1 Discuss the following theorems with respect to Splay Trees- Balance Theorem Dynamic Finger Theorem   Question 2 Write a C program for implementation

Algorithm, Ask question #MWhich of the following is not a characteristic of...

Ask question #MWhich of the following is not a characteristic of good algorithm? inimum 100 words accepted#

Depth-first search (dfs) , In this respect depth-first search (DFS) is the...

In this respect depth-first search (DFS) is the exact reverse process: whenever it sends a new node, it immediately continues to extend from it. It sends back to previously explore

Progrrame, how to write a code for for a company , for calculate the salary...

how to write a code for for a company , for calculate the salary pay

Splaying procedure, For splaying, three trees are maintained, the central, ...

For splaying, three trees are maintained, the central, left & right sub trees. At first, the central subtree is the complete tree and left and right subtrees are empty. The target

Sorting, Sort the following array of elements using quick sort: 3, 1, 4, 1,...

Sort the following array of elements using quick sort: 3, 1, 4, 1, 5, 9, 2, 6, 5, 3, 5, 8.

Shortest path dijkstras algorithm, * Initialise d & pi* for each vertex ...

* Initialise d & pi* for each vertex v within V( g ) g.d[v] := infinity  g.pi[v] := nil g.d[s] := 0; * Set S to empty * S := { 0 }  Q := V(g) * While (V-S)

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