Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
One of the simplest circuits is the asynchronous or ' ripple' counter. Below is shown the circuit diagram of a simple 3 stage ripple counter.
The operation of this circuit is based on the fact that the truth table for the JK flip flop is only valid if the clock waveform is falling, i.e. 1->0. Assume the outputs are all zero, the flip flops will not change until the clock on each flip flop falls. The clock in waveform has just fallen ,since the JKa inputs are logic '1' the device will toggle and the output will invert i.e. Qa=1. Flip flop B will not change because the clock waveform on B has risen (0->1) and these devices only functions on a falling edge. The clock in waveform has fallen again, so Qa toggles again (i.e. Qa =0), this has just produced a falling clock on JKb and Qb toggles (i.e. Qab=1) .The device has just counted from 000-> 001->010.
The circuit is called a ripple counter because the clock pulse is slowly rippling through the JK's, hence asynchronous (Not at the same time!) .The limitations of the asynchronous counter is the speed of operation. A rough formula for the maximum speed is when the clock changes before the output changes i.e. F = 1 / n x propagation delay where n = number of stages, propagation delay of one JK
A better technique is to use a synchronous design where all the JK are clocked together so the maximum frequency is only limited by the propagation delay of 1 JK.
The circuit appears to be complex in design, however it is easily realised by using state diagrams. The maximum frequency of operation is again roughly calculated by considering the frequency at which the output just changes before the clock in changes. F = 1/ Propagation delay
Name the materials used in case of Solder and give reasons. Solder : For soft solders tin, lead (in 50-50 ratio) alloy and for hard solders copper- zinc and silver alloy
how to design load forecasting
The property due to which the resistance of some metal or compound vanishes under certain conditions is (A) Semi conductivity. (B) Super conductivity.
Two three-phase, 6.6-kV, wye-connected synchronous generators, operating in parallel, supply a load of 3000 kWat 0.8 power factor lagging. The synchronous impedance per phase ofmac
How is 8255 (Programmable Peripheral Interface) configured if its control registercomprises 9B h. Ans 9BH => 1001 1011 => b6b5=00-> Mode0 b4=0-> Port A as
The distribution transformer is supplying a load at 240 V and 0.8 power factor lagging. The open-circuit and short-circuit test data are given in Example. (a) Determine the frac
The upper end of a hanging chain is fixed whereas the lower end is attached to a mass M. The (massless) links of the chain are ellipses with major axes and minor axes l+a and l-
Q. Suppose a ROM holds a total of 8192 bits. (a) How many bits long would the individual addresses have to be? (b) If the bits are organized into 8-bit memory words or bytes,
Q. Sketch the asymptotic Bode plots for the following loop-gain functions, and find the approximate values of gain and phase margins in each case.
Q. A 75-kVA, 230/115-V, 60-Hz transformer was tested with these results: • Open-circuit test: 115 V, 16.3 A, 750 W • Short-circuit test: 9.5 V, 326 A, 1200 W Determine:
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd