area under curve , Computer Engineering

Assignment Help:


Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can be found by doing a definite integral between the two points

 

#include 
float
    start_point,            /* GLOBAL VARIABLES */

end_point, total_area; int numtraps; main( ) { void input(void ); float find_area(float a,float b,int n); /* prototype */
print(“AREA UNDER A CURVE”); input( ); total_area = find_area(start_point, end_point, numtraps); printf(“TOTAL AREA = %f”, total_area); } void input(void ) { printf(“\n Enter lower limit:”); scanf(“%f”, &start_point); printf(“Enter upper limit:”); scanf(“%f”, &end_point); printf(“Enter number of trapezoids:”); scanf(“%d”, &numtraps); } float find_area(float a, float b, int n) { float base , lower, h1, h2; /* LOCAL VARIABLES */
float function_x(float x); /* prototype */
float trap_area(float h1,float h2,float base );/*prototype*/
base = (b-1)/n; lower = a; for (lower =a; lower <= b-base ; lower = lower + base ) { h1 = function_x(lower); h1 = function_x(lower + base ); total_area += trap_area(h1, h2, base ); } return (total_area); float trap_area(float height_1,float height_2,float base ) { float area; /* LOCAL VARIABLE */
area = 0.5 * (height_1 + height_2) * base ; return (area); } float function_x(float x) { /* F(X) = X * X + 1 */
return (x*x + 1); } Output AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 30 TOTAL AREA = 12.005000 AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 100 TOTAL AREA = 12.000438


Related Discussions:- area under curve

standard console application, Three projects as follows: a. Life  stati...

Three projects as follows: a. Life  static library, code for every needed  function in the Life program. b. LifeGame  .exe application, i.e., a standard console application t

Concept of pipelining, Describe the concept of pipelining. Ans: Pipeli...

Describe the concept of pipelining. Ans: Pipelining is the means of executing machine instructions concurrently. This is the effective way of organizing concurrent activity in

Example to show directory in doc, Q. Example to show directory in doc? ...

Q. Example to show directory in doc? Like a file name, the directory name may also have up to eight alpha-numeric characters. The directory name can also have an extension

Table - tr and td tags, Table, TR and TD Tags Three tags form the essen...

Table, TR and TD Tags Three tags form the essential ingredients for creating a table. TABLE: This is the main tag. It tells the browser that a table follows. It has attrib

What are the concerns for growth of e-commerce in india, What are the conce...

What are the concerns for growth of e-commerce in India? Government as Facilitator for the growth of e-commerce has taken following steps: a. Promotion of competitive dataco

Explain high level data link control, Explain High Level Data Link Control....

Explain High Level Data Link Control. HDLC - it is High Level Data Link Control: Protocol Overall explanation: Layer 2 of the OSI model is the data link layer. One of the

Advantages and disadvantages of shared memory programming, Q. Show Advantag...

Q. Show Advantages and Disadvantages of Shared Memory Programming? Advantages of Shared Memory Programming Data sharing between processes is both rapid and uniform bec

Tightly coupled system- shared memory system, Tightly Coupled System- Share...

Tightly Coupled System- Shared Memory System Shared memory multiprocessorshas has following description: Every processor commune through a shared global memory. For

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd