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Each of the series 3+5+7+..... and 4+7+10.......... is continued to 100 terms find how many terms are identical.Ans) 48 terms would be common to both the series...first take common terms in both series..7, 13,.....so,this has a common difference of 4 starting with 7.now last term of the given series are 201 and 301 respectively..So we can end our calculation by checking upto 201.201=7+(n-1)4----->n=48(we have to take integer nearest to it)
1) Let the Sample Space S = {1, 2, 3, 4, 5, 6, 7, 8}. Suppose each outcome is equally likely. Compute the probability of event E = "an even number is selected". P(E) = 2) A s
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lim(x->0) xln²(xln(x))
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how much is this
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