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Each of the series 3+5+7+..... and 4+7+10.......... is continued to 100 terms find how many terms are identical.Ans) 48 terms would be common to both the series...first take common terms in both series..7, 13,.....so,this has a common difference of 4 starting with 7.now last term of the given series are 201 and 301 respectively..So we can end our calculation by checking upto 201.201=7+(n-1)4----->n=48(we have to take integer nearest to it)
Evaluate following limits. Solution Here the first two parts are actually just the basic limits including inverse tangents and can easily be found by verifying the fol
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Evaluate following limits. Solution : Let's do the first limit & in this case it sees like we will factor a z 3 out of the numerator and denominator both. Remember that
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