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Each of the series 3+5+7+..... and 4+7+10.......... is continued to 100 terms find how many terms are identical.Ans) 48 terms would be common to both the series...first take common terms in both series..7, 13,.....so,this has a common difference of 4 starting with 7.now last term of the given series are 201 and 301 respectively..So we can end our calculation by checking upto 201.201=7+(n-1)4----->n=48(we have to take integer nearest to it)
Give me the power series solution of Halm''s differential equation
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Uh on my homework it says 6m = $5.76 and I dont get it..
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Let a 0 , a 1 ::: be the series recursively defined by a 0 = 1, and an = 3 + a n-1 for n ≥ 1. (a) Compute a 1 , a 2 , a 3 and a 4 . (b) Compute a formula for an, n ≥ 0.
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