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In this unit, the following four advanced data structures have been practically emphasized. These may be considered as alternative to a height balanced tree, i.e., AVL tree.
The key factors that have been discussed in this unit about the above mentioned data structures include complexity of code in terms of Big oh notation, cost involved in searching a node, the process of deletion of a node and the cost involved in inserting a node.
After going through this unit, you should be able to:
Explain the halting problem Given a computer program and an input to it, verify whether the program will halt on that input or continue working indefinitely on it.
How can a lock object be called in the transaction? By calling Enqueue and Dequeue in the transaction.
Hubs - In reality a multiport repeater - Connects stations in a physical star topology - As well may create multiple levels of hierarchy to remove length limitation of 10
Write c++ function to traverse the threaded binary tree in inorder traversal
Determine about the logic gates Many electronic circuits operate using binary logic gates. Logic gates essentially process signals that represent true or false or equivalent i.
Explain the Interfaces in Ruby Recall that in object-oriented programming, an interface is a collection of abstract operations that cannot be instantiated. Even though Ruby i
Which sorting algorithms does not have a worst case running time of O (n 2 ) ? Merge sort
AVL trees are applied into the given situations: There are few insertion & deletion operations Short search time is required Input data is sorted or nearly sorted
What do you mean by complexity of an algorithm? The complexity of an algorithm M is the function f(n) which gives the running time and/or storage space need of the algorithm i
Explain All-pair shortest-paths problem Given a weighted linked graph (undirected or directed), the all pairs shortest paths problem asks to find the distances (the lengths of
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