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Illustration 1
In a described exam the scores for 10 students were given as:
Student
Mark (x)
|x-x¯|
A
60
1.8
B
45
16.8
C
75
13.2
D
70
8.2
E
65
3.2
F
40
21.8
G
69
7.2
H
64
2.2
I
50
11.8
J
80
18.2
Total
618
104.4
Required
Find out the absolute mean deviation
Mean, x¯ = 618/10 = 61.8
(a+b+c)2=
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write as a percent 6/10
Frequency Distribution or Variance Ratio Distribution This was developed by R. A Fisher in 1924 and is normally defined in terms of the ratio of the variances of two usually d
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17/58-5/87+7/18
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