Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
2(sin 6?+cos6?) - 3(sin4?+cos4?)+1 = 0
Ans: (Sin2?)3 + (Cos2?)3-3 (Sin4?+(Cos4?)+1=0
Consider (Sin2?)3 +(Cos2?)3
⇒(Sin2?+Cos2?)3-3 Sin2?Cos2?( Sin2?+Cos2?)
= 1- 3Sin2? Cos2?
Sin4?+Cos4?(Sin2?)2+(Cos2?)2
= (Sin2?+Cos2?)2-2 Sin2? Cos2?
= 1- 2 Sin2? Cos2?
= 2(Sin6?+Cos6?)-3(Sin4?+Cos4?) +1
= 2 (1-3 Sin2? Cos2?)-3 (1-2 Sin2?+Cos2?)+1
y'' + 2y = 2 - e-4t, y(0) = 1 use euler''s method with a step size of 0.2 to find and approximate values of y
Consider the subsequent IVP. y' = f(t,y) , y(t 0 ) = y 0 If f(t,y) and ∂f/∂y are continuous functions in several rectangle a o - h o + h which is included in a
Table shows the productivity for the countries Pin and Pang. 1) If the working population of Pin and Pang are both 6 million, divided equally between the two industries in
my qustion is how do you muliply frations
Find out the greater of two consecutive positive odd integers whose product is 143. Let x = the lesser odd integer and let x + 2 = the greater odd integer. Because product is a
i need help with 3x+5y=7 2x-5y=8
y=3x^2+12+11
What is the square root of 36? To search the square root (√) you ask yourself, "What number multiplied through itself gives me 36?" 6 .6 = 36; thus, 6 is the square root of 36.
25 cookies have to be divided equally among 4 children.hw can we use elps to answer this question?
1. Find the number of zeroes of the polynomial y = f(x) whose graph is given in figure. 2 Find the circumcentre of the triangle whose vertices are (-2, -3), (-1, 0) and (7,-6).
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd