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I didn't understand the concept of Transpose of a Matrix, need assistance.
If the roots of the equation (a-b) x 2 + (b-c) x+ (c - a)= 0 are equal. Prove that 2a=b+c. Ans: (a-b) x 2 + (b-c) x+ (c - a) = 0 T.P 2a = b + c B 2 - 4AC = 0
please tell me what is algebra and how i can understand it
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Answer: The transpose of a matrix A order of mxn is the nxm matrix AT acquired by interchanging the rows and columns of A. A = [aij] The transpose of A that is AT is given by AT = [ aij ]mxn = [ aji ]nxm
Answer:
The transpose of a matrix A order of mxn is the nxm matrix AT acquired by interchanging the rows and columns of A.
A = [aij]
The transpose of A that is AT is given by
AT = [ aij ]mxn = [ aji ]nxm
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