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1) A company gets a sample of 64 customers (n=64) and calculates the sample mean(X bar) of customer spending per week to be $85. Assume the company has calculated the population standard deviation of customer spending to be o=$8 and that this variable is normally distributed , calculate the following: a) A 90% confidence interval estimate of the population mean u b) A 95% confidence interval estimate of the population mean u c) How would you explain the confidence interval you found in (a) to a news reporter who needs to report this on national television? 2) A major cell phone service provider has determined that the number of minutes that its customers use their phone is normally distributed with a mean of 450 minutes and a standard deviation of 50 minutes. The company is thinking of offering a discount to those who use the phone for less than 250 mins. during a given month. Based on the available information, answer the ff. a) How many minutes does a person use when the standardized Z score equals -2, -1, 0,1 and 2? b) What percentage of current customers would be eligible for the discount? 3) Information given: ** The manager of a paint store wants to know whether paint per can averages 1 gallon ** Population standard deviation of the paint weight o=0.02 gallons. ** The manager takes a random sample of 50 paint cans(n=50) ** He finds the sample mean to be (X bar)=0.995 gallons. a) State the Null and Alternative Hypotheses: b) At a 95% confidence level, test whether the null hypothesis is correct. 4) If you use a 0.05 level of significance in a two-tail hypothesis test, what will you decide if the computed value of the test statistics is Z=2.21?
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