What is the equilibrium mole fraction of ammonia

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For the ammonia synthesis reaction,

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the equilibrium conversion to ammonia is large at 300 K, but decreases rapidly with increasing T. However, reaction rates become appreciable only at higher temperatures. For a feed mixture of hydrogen and nitrogen in the stoichiometric proportions,

(a) What is the equilibrium mole fraction of ammonia at 1 bar and 300 K?

(b) At what temperature does the equilibrium mole fraction of ammonia equal 0.50 for a pressure of 1 bar?

(c) At what temperature does the equilibrium mole fraction of ammonia equal 0.50 for a pressure of 100 bar, assuming the equilibrium mixture is an ideal gas?

(d) At what temperature does the equilibrium mole fraction of ammonia equal 0.50 for a pressure of 100 bar, assuming the equilibrium mixture is an ideal solution of gases?

Reference no: EM131194253

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