Values for pv based on the ideal gas law

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Focus Question: How does the volume of mole of methane gas at 300 bar and 298K compare to the volume of one mole of an ideal gas at 300 bar and 298K?

Important Formula: For real gases P=nRT/V-nb, z=PV‾/RT where V‾ is the volume of one mole of gas

  1. Assume the container has volume of 24.789L and that is contains 1 mole of real gas. At 25C will the gas have a greater or lower pressure than an ideal gas?
  2. For methane, b=0.0428L/mole. Calculate P, PV and Z for methane at 25C for the volumes listed in the table below

Volume (L)

Pressure (bar)

PV (L bar)

Z

247.9

 

 

 

123.99

 

 

 

24.79

 

 

 

4.958

 

 

 

2.479

 

 

 

0.2479

 

 

 

  1. Calculate the values for PV based on the ideal gas law and add this column to your table.
  2. How do these compare?
  3. Are the values for Z higher or lower than those predicted by the ideal gas law?
  4. Draw a graph of Z vs. P for an ideal gas and for methane.

Once you have answered these go back and write a few (3-5) paragraphs explaining the answer to the focus question in the context of the answers to the other questions. Include APPA style references

Reference no: EM13943385

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Values for pv based on the ideal gas law : Focus Question: How does the volume of mole of methane gas at 300 bar and 298K compare to the volume of one mole of an ideal gas at 300 bar and 298K?
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